$application of diffraction of sound waves$

$application of diffraction of sound waves$

Application of diffraction of sound waves series#

The figure below shows an exact simulation of light passing through an aperture which is 3 wavelengths wide: We’ve mentioned above that diffraction is only appreciable when light interacts with objects of size comparable to the wavelength, and this is true of light passing through the slit, as well. Some of the light has evidently ‘bent around the corner’ on passing through the aperture, and this is what we mean by diffraction. More important for our discussion, however, is what happens when light passes through the aperture: not only are there bright and dark patches indicative of interference, but we can see that the light is spreading in a cone away from the aperture, at odds with the simple geometric prediction. These are locations where the incident field from below is interfering with the field which gets reflected from the metal plate.

$application of diffraction of sound waves$

Two things are different from the geometric picture: below the aperture, there are horizontal lines of darkness along with the bright lines.

$application of diffraction of sound waves$

The second picture is an exact numerical simulation of Maxwell’s equations, demonstrating what ‘actually’ happens when light illuminates a wavelength-wide slit. Those rays which hit the metal plate are absorbed or reflected, while the rays illuminating the aperture pass directly through unimpeded and form a ‘column’ of light. Geometric theory models light as traveling along definite paths (rays) in space, indicated on the picture by arrowed lines. The first picture indicates the prediction of geometrical optics.

$application of diffraction of sound waves$

one wavelength), and overall the images are 4000 nm by 4000 nm. The wavelength is taken to be 500 nm, the aperture width is 500 nm (i.e. In both pictures, we have a collimated (one-directional) field incident from below upon an aperture in a silver plate (represented in cyan here). In both pictures, higher light intensity is represented by brighter color. To give you an example of how a diffracted field would differ from a field propagated geometrically, we consider the case of light traveling through a narrow slit in a metal plate: Wavelengths of sound can range between millimeters and meters (comparable to a farmhouse) while wavelengths of visible light are on the order of 500 nanometers (0.0000005 meters, or 0.5 micrometers). One can demonstrate theoretically that waves only produce appreciable diffraction when interacting with objects of a size comparable to or smaller than the wavelength. This is because the wavelength of visible light (to be discussed in part IV of optics basics) is much smaller than the wavelength of sound. Light waves also diffract, though the effect is much smaller and difficult to detect. The sound waves wrap around (diffract around) the outside of the farmhouse, allowing communication. We all have experienced the diffraction of sound waves: if you and a friend stand on opposite sides of a large building (say a farmhouse) in the middle of an open field, you will be able to talk to each other even though there is no direct ‘line of sight’ between you and your friend, and no ability for the sound waves to reflect off of intermediate surfaces. The most significant consequence of this spreading is the ability of waves to ‘bend around corners’ when faced with an obstacle. The second behavior of waves which is extremely significant is diffraction, and we will address it in this post.ĭiffraction may be broadly defined as the tendency of a wave traveling in two or more dimensions to spread out as it propagates.

Application of diffraction of sound waves series#

In part II of my series on ‘What is a wave?’, I addressed one of the two most significant behaviors of waves, namely interference, the ability of a wave to ‘interact’ with itself.

$application of diffraction of sound waves$